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Vehicle Service

in C++ | 2018-09-23

Difficulty : Beginner

By DePaul Dimadis

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Define a class named Vehicle_Service with the following private data members:

    1. Vehicle registration number (int type)

    2. Working hours (double type) needed to repair the vehicle

    3. Cost of spare parts required for repair

    4. Total repair cost (double type)

The class must contain member functions for the following:

    1. Entering values in private data members of class

    2. Returning the value of each private data member (get_number(), get_hours (), get_parts_cost(), get_total_cost()

    3. Printing out the private members

    The main () function:

    1. Defines an array of 10 class objects
    2. Will enter data in the object array
    3. It will display all the contents of the array
    4. Find and display (using all objects in the array):
       a. The total number of working hours
       b. The total cost of spare parts
       c. The total repair cost

#include <iostream>
#define N 10
using namespace std;

class vehicle_service
{
private :
	int ar_k;
	double maint;
	double cost;
    double sumcost;
public :
	int setar_k(int t)
	{
		ar_k=t;
		return 0;
	};
	double setmaint(double r)
	{
		maint=r;
		return 0;
	};
    double setcost(double p)
	{
		cost=p;
		return 0;
	};
    double setsumcost(double x)
	{
		sumcost=x;
		return 0;
	};
	void print_members(){
		cout << ar_k << endl;
		cout << maint << endl;
		cout << cost << endl;
		cout << sumcost << endl;
	};
	int getar_k()
	{		
		return ar_k;
	};

    double getmaint()
	{
		return maint;
	};

     double getcost()
	{
		return cost;
	};

    double getsumcost()
	{
		return sumcost;
	};
};   //end class

void main()
{
	double r,p,x,sum1=0.0,sum2=0.0,sum3=0.0;
	int t;
	vehicle_service a[N];
	for (int i=0;i<N;i++)
	{
		t=rand()%100;
	    r=rand()%100*1.0;
		x=rand()%100*1.0;
		p=rand()%100*1.0;
		a[i].setar_k(t);
		a[i].setcost(p);
		a[i].setmaint(r);
		a[i].setsumcost(x);
		a[i].print_members();
	}  //end for
	for(int i=0;i<N;i++)
	{
		sum1+=a[i].getmaint();
		sum2+=a[i].getcost();
		sum3+=a[i].getsumcost();
	}  //end second for
	cout << endl << endl ;
	cout<<sum1<<endl<<sum2<<endl<<sum3<<endl;
    
}

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